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devdraw: accept 5- and 6-byte Unicode hex values

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Alt X 1234 for U+1234
Alt X X 12345 for U+12345
Alt X X X 103456 for U+103456.
This commit is contained in:
Russ Cox 2020-05-29 21:19:32 -04:00
parent 2c70acc3ab
commit 3850e6e177
2 changed files with 45 additions and 15 deletions
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21
man/man7/keyboard.7
View file

@ -58,7 +58,7 @@ The up arrow scrolls backward.
.PP
Characters in Plan 9 are runes (see
.IR utf (7)).
Any 16-bit rune can be typed using a compose key followed by several
Any rune can be typed using a compose key followed by several
other keys.
The compose key is also generally near the lower right of the main key area:
the
@ -72,14 +72,21 @@ key on the SLC, the
key on the Magnum, and either
.B Alt
key on the PC.
After typing the compose key, type a capital
.L X
and exactly four hexadecimal characters (digits and
To type a single rune with the value specified by
a given four-digit hexadecimal number,
type the compose key,
then a capital
.LR X ,
and then the four hexadecimal digits (decimal digits and
.L a
to
.LR f )
to type a single rune with the value represented by
the typed number.
.LR f ).
For a longer rune, type
.L X
twice followed by five digits,
or type
.L X
three times followed by six digits.
There are shorthands for many characters, comprising
the compose key followed by a two- or three-character sequence.
The full list is too long to repeat here, but is contained in the file

39
src/cmd/devdraw/latin1.c
View file

@ -17,16 +17,15 @@ static struct cvlist
};
/*
* Given 5 characters k[0]..k[4], find the rune or return -1 for failure.
* Given 5 characters k[0]..k[n], find the rune or return -1 for failure.
*/
static long
unicode(Rune *k)
unicode(Rune *k, int n)
{
long i, c;
k++; /* skip 'X' */
c = 0;
for(i=0; i<4; i++,k++){
for(i=0; i<n; i++,k++){
c <<= 4;
if('0'<=*k && *k<='9')
c += *k-'0';
@ -36,6 +35,8 @@ unicode(Rune *k)
c += 10 + *k-'A';
else
return -1;
if(c > Runemax)
return -1;
}
return c;
}
@ -53,10 +54,32 @@ latin1(Rune *k, int n)
char* p;
if(k[0] == 'X'){
if(n>=5)
return unicode(k);
else
return -5;
if(n < 2)
return -2;
if(k[1] == 'X') {
if(n < 3)
return -3;
if(k[2] == 'X') {
if(n < 9) {
if(unicode(k+3, n-3) < 0)
return -1;
return -(n+1);
}
return unicode(k+3, 6);
}
if(n < 7) {
if(unicode(k+2, n-2) < 0)
return -1;
return -(n+1);
}
return unicode(k+2, 5);
}
if(n < 5) {
if(unicode(k+1, n-1) < 0)
return -1;
return -(n+1);
}
return unicode(k+1, 4);
}
for(l=latintab; l->ld!=0; l++)