mirror of
https://github.com/9fans/plan9port.git
synced 2025-01-15 11:20:03 +00:00
5993a8f275
at least it can handle "diff file1 file2 dir".
419 lines
8.6 KiB
C
419 lines
8.6 KiB
C
#include <u.h>
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#include <libc.h>
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#include <bio.h>
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#include "diff.h"
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/* diff - differential file comparison
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*
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* Uses an algorithm due to Harold Stone, which finds
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* a pair of longest identical subsequences in the two
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* files.
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*
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* The major goal is to generate the match vector J.
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* J[i] is the index of the line in file1 corresponding
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* to line i file0. J[i] = 0 if there is no
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* such line in file1.
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*
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* Lines are hashed so as to work in core. All potential
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* matches are located by sorting the lines of each file
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* on the hash (called value). In particular, this
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* collects the equivalence classes in file1 together.
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* Subroutine equiv replaces the value of each line in
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* file0 by the index of the first element of its
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* matching equivalence in (the reordered) file1.
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* To save space equiv squeezes file1 into a single
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* array member in which the equivalence classes
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* are simply concatenated, except that their first
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* members are flagged by changing sign.
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*
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* Next the indices that point into member are unsorted into
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* array class according to the original order of file0.
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*
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* The cleverness lies in routine stone. This marches
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* through the lines of file0, developing a vector klist
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* of "k-candidates". At step i a k-candidate is a matched
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* pair of lines x,y (x in file0 y in file1) such that
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* there is a common subsequence of lenght k
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* between the first i lines of file0 and the first y
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* lines of file1, but there is no such subsequence for
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* any smaller y. x is the earliest possible mate to y
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* that occurs in such a subsequence.
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*
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* Whenever any of the members of the equivalence class of
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* lines in file1 matable to a line in file0 has serial number
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* less than the y of some k-candidate, that k-candidate
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* with the smallest such y is replaced. The new
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* k-candidate is chained (via pred) to the current
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* k-1 candidate so that the actual subsequence can
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* be recovered. When a member has serial number greater
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* that the y of all k-candidates, the klist is extended.
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* At the end, the longest subsequence is pulled out
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* and placed in the array J by unravel.
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*
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* With J in hand, the matches there recorded are
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* check'ed against reality to assure that no spurious
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* matches have crept in due to hashing. If they have,
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* they are broken, and "jackpot " is recorded--a harmless
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* matter except that a true match for a spuriously
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* mated line may now be unnecessarily reported as a change.
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*
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* Much of the complexity of the program comes simply
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* from trying to minimize core utilization and
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* maximize the range of doable problems by dynamically
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* allocating what is needed and reusing what is not.
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* The core requirements for problems larger than somewhat
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* are (in words) 2*length(file0) + length(file1) +
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* 3*(number of k-candidates installed), typically about
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* 6n words for files of length n.
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*/
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/* TIDY THIS UP */
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struct cand {
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int x;
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int y;
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int pred;
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} cand;
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struct line {
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int serial;
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int value;
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} *file[2], line;
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int len[2];
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int binary;
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struct line *sfile[2]; /*shortened by pruning common prefix and suffix*/
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int slen[2];
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int pref, suff; /*length of prefix and suffix*/
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int *class; /*will be overlaid on file[0]*/
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int *member; /*will be overlaid on file[1]*/
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int *klist; /*will be overlaid on file[0] after class*/
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struct cand *clist; /* merely a free storage pot for candidates */
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int clen;
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int *J; /*will be overlaid on class*/
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long *ixold; /*will be overlaid on klist*/
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long *ixnew; /*will be overlaid on file[1]*/
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/* END OF SOME TIDYING */
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static void
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sort(struct line *a, int n) /*shellsort CACM #201*/
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{
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int m;
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struct line *ai, *aim, *j, *k;
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struct line w;
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int i;
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m = 0;
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for (i = 1; i <= n; i *= 2)
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m = 2*i - 1;
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for (m /= 2; m != 0; m /= 2) {
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k = a+(n-m);
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for (j = a+1; j <= k; j++) {
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ai = j;
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aim = ai+m;
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do {
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if (aim->value > ai->value ||
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aim->value == ai->value &&
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aim->serial > ai->serial)
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break;
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w = *ai;
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*ai = *aim;
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*aim = w;
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aim = ai;
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ai -= m;
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} while (ai > a && aim >= ai);
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}
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}
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}
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static void
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unsort(struct line *f, int l, int *b)
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{
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int *a;
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int i;
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a = MALLOC(int, (l+1));
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for(i=1;i<=l;i++)
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a[f[i].serial] = f[i].value;
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for(i=1;i<=l;i++)
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b[i] = a[i];
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FREE(a);
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}
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static void
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prune(void)
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{
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int i,j;
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for(pref=0;pref<len[0]&&pref<len[1]&&
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file[0][pref+1].value==file[1][pref+1].value;
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pref++ ) ;
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for(suff=0;suff<len[0]-pref&&suff<len[1]-pref&&
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file[0][len[0]-suff].value==file[1][len[1]-suff].value;
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suff++) ;
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for(j=0;j<2;j++) {
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sfile[j] = file[j]+pref;
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slen[j] = len[j]-pref-suff;
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for(i=0;i<=slen[j];i++)
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sfile[j][i].serial = i;
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}
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}
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static void
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equiv(struct line *a, int n, struct line *b, int m, int *c)
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{
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int i, j;
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i = j = 1;
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while(i<=n && j<=m) {
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if(a[i].value < b[j].value)
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a[i++].value = 0;
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else if(a[i].value == b[j].value)
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a[i++].value = j;
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else
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j++;
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}
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while(i <= n)
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a[i++].value = 0;
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b[m+1].value = 0;
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j = 0;
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while(++j <= m) {
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c[j] = -b[j].serial;
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while(b[j+1].value == b[j].value) {
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j++;
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c[j] = b[j].serial;
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}
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}
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c[j] = -1;
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}
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static int
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newcand(int x, int y, int pred)
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{
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struct cand *q;
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clist = REALLOC(clist, struct cand, (clen+1));
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q = clist + clen;
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q->x = x;
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q->y = y;
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q->pred = pred;
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return clen++;
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}
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static int
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search(int *c, int k, int y)
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{
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int i, j, l;
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int t;
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if(clist[c[k]].y < y) /*quick look for typical case*/
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return k+1;
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i = 0;
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j = k+1;
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while((l=(i+j)/2) > i) {
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t = clist[c[l]].y;
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if(t > y)
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j = l;
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else if(t < y)
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i = l;
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else
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return l;
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}
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return l+1;
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}
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static int
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stone(int *a, int n, int *b, int *c)
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{
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int i, k,y;
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int j, l;
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int oldc, tc;
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int oldl;
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k = 0;
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c[0] = newcand(0,0,0);
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for(i=1; i<=n; i++) {
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j = a[i];
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if(j==0)
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continue;
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y = -b[j];
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oldl = 0;
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oldc = c[0];
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do {
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if(y <= clist[oldc].y)
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continue;
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l = search(c, k, y);
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if(l!=oldl+1)
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oldc = c[l-1];
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if(l<=k) {
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if(clist[c[l]].y <= y)
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continue;
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tc = c[l];
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c[l] = newcand(i,y,oldc);
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oldc = tc;
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oldl = l;
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} else {
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c[l] = newcand(i,y,oldc);
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k++;
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break;
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}
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} while((y=b[++j]) > 0);
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}
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return k;
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}
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static void
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unravel(int p)
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{
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int i;
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struct cand *q;
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for(i=0; i<=len[0]; i++) {
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if (i <= pref)
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J[i] = i;
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else if (i > len[0]-suff)
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J[i] = i+len[1]-len[0];
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else
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J[i] = 0;
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}
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for(q=clist+p;q->y!=0;q=clist+q->pred)
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J[q->x+pref] = q->y+pref;
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}
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static void
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output(void)
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{
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int m, i0, i1, j0, j1;
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m = len[0];
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J[0] = 0;
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J[m+1] = len[1]+1;
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if (mode != 'e') {
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for (i0 = 1; i0 <= m; i0 = i1+1) {
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while (i0 <= m && J[i0] == J[i0-1]+1)
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i0++;
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j0 = J[i0-1]+1;
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i1 = i0-1;
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while (i1 < m && J[i1+1] == 0)
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i1++;
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j1 = J[i1+1]-1;
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J[i1] = j1;
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change(i0, i1, j0, j1);
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}
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}
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else {
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for (i0 = m; i0 >= 1; i0 = i1-1) {
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while (i0 >= 1 && J[i0] == J[i0+1]-1 && J[i0])
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i0--;
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j0 = J[i0+1]-1;
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i1 = i0+1;
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while (i1 > 1 && J[i1-1] == 0)
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i1--;
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j1 = J[i1-1]+1;
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J[i1] = j1;
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change(i1 , i0, j1, j0);
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}
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}
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if (m == 0)
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change(1, 0, 1, len[1]);
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}
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#define BUF 4096
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static int
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cmp(Biobuf* b1, Biobuf* b2)
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{
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int n;
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uchar buf1[BUF], buf2[BUF];
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int f1, f2;
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vlong nc = 1;
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uchar *b1s, *b1e, *b2s, *b2e;
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f1 = Bfildes(b1);
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f2 = Bfildes(b2);
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seek(f1, 0, 0);
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seek(f2, 0, 0);
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b1s = b1e = buf1;
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b2s = b2e = buf2;
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for(;;){
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if(b1s >= b1e){
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if(b1s >= &buf1[BUF])
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b1s = buf1;
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n = read(f1, b1s, &buf1[BUF] - b1s);
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b1e = b1s + n;
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}
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if(b2s >= b2e){
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if(b2s >= &buf2[BUF])
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b2s = buf2;
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n = read(f2, b2s, &buf2[BUF] - b2s);
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b2e = b2s + n;
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}
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n = b2e - b2s;
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if(n > b1e - b1s)
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n = b1e - b1s;
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if(n <= 0)
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break;
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if(memcmp((void *)b1s, (void *)b2s, n) != 0){
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return 1;
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}
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nc += n;
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b1s += n;
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b2s += n;
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}
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if(b1e - b1s == b2e - b2s)
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return 0;
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return 1;
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}
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void
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diffreg(char *f, char *t)
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{
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Biobuf *b0, *b1;
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int k;
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binary = 0;
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b0 = prepare(0, f);
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if (!b0)
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return;
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b1 = prepare(1, t);
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if (!b1) {
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FREE(file[0]);
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Bterm(b0);
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return;
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}
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if (binary){
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// could use b0 and b1 but this is simpler.
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if (cmp(b0, b1))
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print("binary files %s %s differ\n", f, t);
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Bterm(b0);
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Bterm(b1);
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return;
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}
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clen = 0;
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prune();
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sort(sfile[0], slen[0]);
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sort(sfile[1], slen[1]);
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member = (int *)file[1];
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equiv(sfile[0], slen[0], sfile[1], slen[1], member);
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member = REALLOC(member, int, slen[1]+2);
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class = (int *)file[0];
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unsort(sfile[0], slen[0], class);
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class = REALLOC(class, int, slen[0]+2);
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klist = MALLOC(int, slen[0]+2);
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clist = MALLOC(struct cand, 1);
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k = stone(class, slen[0], member, klist);
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FREE(member);
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FREE(class);
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J = MALLOC(int, len[0]+2);
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unravel(klist[k]);
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FREE(clist);
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FREE(klist);
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ixold = MALLOC(long, len[0]+2);
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ixnew = MALLOC(long, len[1]+2);
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Bseek(b0, 0, 0); Bseek(b1, 0, 0);
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check(b0, b1);
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output();
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FREE(J); FREE(ixold); FREE(ixnew);
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Bterm(b0); Bterm(b1); /* ++++ */
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}
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